y^2-8y+28=0

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Solution for y^2-8y+28=0 equation:


Simplifying
y2 + -8y + 28 = 0

Reorder the terms:
28 + -8y + y2 = 0

Solving
28 + -8y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-28' to each side of the equation.
28 + -8y + -28 + y2 = 0 + -28

Reorder the terms:
28 + -28 + -8y + y2 = 0 + -28

Combine like terms: 28 + -28 = 0
0 + -8y + y2 = 0 + -28
-8y + y2 = 0 + -28

Combine like terms: 0 + -28 = -28
-8y + y2 = -28

The y term is -8y.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8y + 16 + y2 = -28 + 16

Reorder the terms:
16 + -8y + y2 = -28 + 16

Combine like terms: -28 + 16 = -12
16 + -8y + y2 = -12

Factor a perfect square on the left side:
(y + -4)(y + -4) = -12

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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